Question

$(2i {}^{3}) {}^{2} in \: a + ib \: form$
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Answer 1

Step-by-step explanation:

$(2 {i}^{3} )^{2} = {2}^{2} {i}^{3 \times 2} = 4 ({i ^{2} })^{3} \\ = 4( - 1) ^{3} \\ = 4( - 1) \\ = - 4 \\ = - 4 + 0i \implies \: a + ib \\ where \: \\ a = - 4 \\ b = 0$

Answer 2

Answer:

See the above attachment

hope it helps you