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Step-by-step explanation:
What is the value of 2^ (log base (2 sqrt(2)) of 15) =?
Let T=2log22√15
Recall that logba≡logcalogcb . We can use this to convert our logarithms to base 2.
∴log22√15=log215log222–√
Recall that logab≡loga+logb , and logbba≡a .
∴log222–√=log22+log22–√=log221+log2212=1+12=32
∴log22√15=log21532=23log215
∴T=223log215
Recall that abc≡(ab)c .
∴T=(2log215)23
Recall that blogba≡a .
∴T=1523≈6.0822
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