Question

$2m {}^{2} - 19m + 30 = 0$
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Answer 1

Answer:

2m²-19m+30=0

2m²-4m-15m+30=0

2m(m-2)-15(m-2)=0

(2m-15)(m-2)=0

m=2 or 15/2

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Answer 2

Answer:

Step-by-step explanation:

Given

2m^2 - 10m + 30 = 0

2 ( m^2 - 5m + 15 ) = 0

m^2 - 5m + 15 = 0 / 2

m^2 - 5m + 15 = 0

Now compare the given polynomial with standard polynomial ax^2 + bx +c = 0,

We have a =1 , b = -5 , c = 15

So, x = -b ± √b^2 - 4ac / 2a

= - ( -5 ) ± √ ( -5 )^2 - 4 × 1 × 15 / 2 × 1

= 5 ± √ 25 - 60 / 2

= 5 ± √ 35 / 2

Hence x = 5 + √35 / 2 or 5 - √35 / 2 is the answer.