Question

$(2x + 1 \div x) ^{3}$
​

Answer 1

I hope it will help you

Answer 2

${\pink{Hola!!}}$

Given:-

$(2x+1\div x)^{3}$

${\frac{{2x+1}^3}{x}}$

using the identity:-

(x+y)³=x³+y³+3x²y+3xy²

${\frac{(2x)^3+(1)^3+3(2x)^2×1+3(2x)×1^2}{x^3}}$

${\frac{8x^3+1+3(4x^2)+3(2x)×1^2}{x^3}}$

${\frac{8x^3+1+4x^2+6x}{x^3}}$

${\bf{\blue{\huge{\frac{8x^3+4x^2+6x+1}{x^3}}}}}$



$<marquee>$#Bebrainly❤️✨✔️❤️✨✔️