![{2x}^{2} - 10x - 55 = 0 {2x}^{2} - 10x - 55 = 0](https://tex.z-dn.net/?f=+%7B2x%7D%5E%7B2%7D++-+10x+-+55+%3D+0)
using factorisation method
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1
Answer:
x= -5 , x= 21/2
Step-by-step explanation:
2x^2 -11x+10x-55
x(2x-11) +5(2x-11)
x+5=0, 2x-11=0
x=0-5, 2x=10+11
x=-5, 2x=21
x= -5 , x= 21/2
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