Question

${2x}^{2} + 19x - 10$
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Answer 1

$2 {x}^{2} + 19x - 10 \\ = 2 {x}^{2} + (20 - 1)x - 10 \\ = 2 {x}^{2} + 20x - x - 10 \\ = 2x(x + 10) - 1(x + 10) \\ = (2x - 1)(x + 10)$

Answer 2

$\mathfrak{\underline{\underline{\red{Answer:-}}}}$

$\pink{x = -10}$

$\pink{x = \dfrac{1}{2}}$

$\mathfrak{\underline{\underline{\red{Explanation:-}}}}$

$\mathbf{let, {2x}^{2}+19x-10= 0}$

Now,

$\mathbf{{2x}^{2}+20x-x -10 = 0}$

$\mathbf{2x(x+10)-1(x+10)= 0}$

$\mathbf{(x+10)(2x-1)= 0}$

$\boxed{\green{x = -10}}$

$\boxed{\green{x = \dfrac{1}{2}}}$