Question

$2x { }^{2} - 2 \sqrt{2 } + 1 = 0$
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Answer 1

hope you got your answer

Answer 2

Answer:

$x = \frac{1}{ \sqrt{2} }$

Step-by-step explanation:

$2 {x}^{2} - 2 \sqrt{2x} + 1 = 0 \\ \\ \therefore \: ( { \sqrt{2x}) }^{2} - 2( \sqrt{2x} )(1) + 1 = 0 \\ \\ \therefore {( \sqrt{2x} - 1) }^{2} = 0 \\ \\ \therefore \sqrt{2x} - 1 = 0 \\ \\ \therefore \: \sqrt{2x} = 1 \\ \\ \therefore \: x = \frac{1}{ \sqrt{2} }$