Math, asked by darshancris7, 9 months ago

$2x^{2} +2\sqrt{2} x-6$

Answers

Answered by sishita753

1

Answer:

$2 {x}^{2} +2 \sqrt{x} - 6 = 0 \\ {x}^{2}+ \sqrt{x} - 3 = 0 \\ by solving we get \\ x = 1/ \sqrt{2}, - 3 \sqrt{2}/2$

Answered by sonusharma46

3

hello dear

sharma ji ka londa here

sun sathiya mahiba barsha de - just song

2x^2+ 3 √4x - √4x -6

√2x (√2x +3√2 ) - √2 ( √2 x+3√2) -

(√2x -√2) (√2x+3√2) is your answer

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