Question

$2x ^{2} + 4 ^{3} + 6x ^{2} \div 2x$
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Answer 1

$\large{\implies{Answer}}$

$= \frac{2x {}^{2} + 4 {x}^{3} + 6x {}^{2} }{2x} \\ = \frac{8x {}^{2} + 4x {}^{3} }{2x} \\ = 2x \times \frac{4x {}^{} + 2x {}^{2} }{2x} \\ = 2x {}^{2} + 4x$

Answer 2

Here is your answer ❤️...