Question

$({2x}^{2} - 4x + 5)( {x}^{2} + 3x - 7)$

Answer 1

Hey mate...here is ur ans...✌❤❤

$(2x {}^{2} - 4x + 5)(x {}^{2} + 3x - 7) \\ \\ 2 {x}^{2} - 4x + 5 \ \: \times {x}^{2} + 3x - 7 \\ \\ 2 {x }^{2} (x {}^{2} + 3x - 7) - 4x(x { }^{2} + 3x - 7) + 5( {x}^{2} + 3x - 7) \\ \\ 2 { {x}^{4} }^{} + 6x { {}^{3} }^{} - 14x {}^{2} - 4x {}^{3 } - 12 {x}^{2} - 28x + 5 {x}^{2} + 15x - 35 \\ \\ 2 {x} {}^{4} + 6 {x}^{3 } - 4 {x}^{3} - 14 {x}^{2} - 12 {x}^{2} + 5 {x}^{2} - 28x + 15x - 35 \\ \\ 2 {x}^{4} + 2 {x}^{3} - 21 {x}^{2} - 13x - 35$

Hope it helps u...thanks...✌❤❤