Question

$2x {}^{2} + 7x + 3$
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Answer 1

Answer:

IT'S 2X^2+7X+3=0

2X^2+(6+1)x+3=0

2X^2+6X+X+3=0

2X (X+3)+1 (X+3)=0

(X+3)(2X+1)=0

X=-3 & X=-1/2.

HOPE THIS WILL HELP YOU DEAR.

♥

Answer 2

Answer:

Bro, you just gave the equation without telling what to solve! But yet, I made some effort to give multiple answers:

1. The graph is given in the file attached below.

2. The zeros of the equation are also shown in the graph attached, but we will split the middle term and solve. And BTW, the equation has two eros because it is intersecting the y-axis at 2 distinct points.

2x²+7x+3=0

2x²+6x+1x+3=0

2x(x+3)+1(x+3)=0

(2x+1)(x+3)=0

Thus, 2x+1=0 ; x+3=0

2x= -1 ; x= -3

x= -1/2 ; x= -3

Thus, the zeros are -1/2, -3.

3. 2x²+7x+3=0 is a quadratic equation because the highest degree is 2.

HOPE THIS HELPS :D