Question

$2x ^{2} + 7x + 3$
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Answer 1

Answer:

$2x ^{2} + 7x + 3 \\ \\ = 2 x^{2} + (6 + 1)x + 3 \\ \\ = 2x ^{2} + 6x + x + 3 \\ \\ = 2x(x + 3) + 1(x + 3) \\ \\ = (2x + 1)(x + 3) \\ \\ either \: 2x + 1 = 0 \\ \\ = > x = \frac{ - 1}{2} \\ \\ or \: x + 3 = 0 \\ \\ = > x = - 3$

hope it helps uH ✔

Answer 2

Answer:

2x²+7x+3=0

2x²+(6+1)x+3=0

2x²+6x+x+3=0

2x(x+3)+1(x+3)=0

(x+3)(2x+1)=0

Either, or,

x+3=0 2x+1=0

x= -3 2x= -1

x= -1/2