Question

$- 2x {}^{2} + kx + \sqrt{2}$
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Answer 1

Step-by-step explanation:

Given f(x) = 2x^2 + kx + root 2.

Given g(x) = x - 1.

By the Remainder theorem, we get

= > x - 1 = 0

= > x = 1.

Plug x = 1 in f(x), we get

= \ \textgreater \ 2(1)^2 + k(1) + \sqrt{2} = 0

= \ \textgreater \ 2 + k + \sqrt{2} = 0

= \ \textgreater \ k = -2 - \sqrt{2}