Question

$2x {}^{2} - x + \frac{1}{8} = 0$

Answer 1

2x²-x+1/8=0
16x²-8x+1=0
16x²-4x-4x+1=0
4x(4x-1)-1(4x-1)=0
(4x-1)(4x-1)=0
4x-1=0
4x=1
x=1/4

Answer 2

❤❤here is your answer ✌ ✌ In attachment