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Answered by
6
Hey mate..
=========
Given,
2x + 2y = 15 .....(1)
2x - 2y = 5 .....(2)
Subtracting (2) from (1) we get,
=> ( 2x + 2y ) - ( 2x - 2y ) = 15 - 5
=> 2x + 2y - 2x + 2y = 10
=> 4y = 10
=> y = 10/4
=> y = 5/2
Putting the value of y = 5/2 in Eq.(1) we have,
2x + 2 × 5/2 = 15
=> 2x + 5 = 15
=> 2x = 10
=> x = 10/2
=> x = 5
Thus,
The required value of x and y are 5 and 5/2 respectively.
Hope it helps !!
=========
Given,
2x + 2y = 15 .....(1)
2x - 2y = 5 .....(2)
Subtracting (2) from (1) we get,
=> ( 2x + 2y ) - ( 2x - 2y ) = 15 - 5
=> 2x + 2y - 2x + 2y = 10
=> 4y = 10
=> y = 10/4
=> y = 5/2
Putting the value of y = 5/2 in Eq.(1) we have,
2x + 2 × 5/2 = 15
=> 2x + 5 = 15
=> 2x = 10
=> x = 10/2
=> x = 5
Thus,
The required value of x and y are 5 and 5/2 respectively.
Hope it helps !!
Answered by
3
heya friend ...✌
Here is your answer...
----------------------------
2x+2y=15 【given】lo lo
2x+2y=5
2x+2y=15
2(x+y)=15
x+y=15/2-----------1)
and again...
2x-2y=5
=>2(x-y)=5..
=>x-y=5/2...............2)
now,,,, if we adding both equations 1). and 2)
we get ......
x+y=15/2
x-y=5/2
----------------
2x=20/2
x=5....now if putting the value on equation 1)
then we get...
x+y=15/2
=>5+y=15/2
y=15/2-5
=>15+10/2
y=5/2=2+1/2 Ans.....
hope it help you...
#@Rajukumar☺☺@
Here is your answer...
----------------------------
2x+2y=15 【given】lo lo
2x+2y=5
2x+2y=15
2(x+y)=15
x+y=15/2-----------1)
and again...
2x-2y=5
=>2(x-y)=5..
=>x-y=5/2...............2)
now,,,, if we adding both equations 1). and 2)
we get ......
x+y=15/2
x-y=5/2
----------------
2x=20/2
x=5....now if putting the value on equation 1)
then we get...
x+y=15/2
=>5+y=15/2
y=15/2-5
=>15+10/2
y=5/2=2+1/2 Ans.....
hope it help you...
#@Rajukumar☺☺@
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