Question

$(2x + 3) {}^{2} = 25$
solve please see the attachment use this method and solve please

kripaya faltu answer na de​

Answer 1

Answer:

☑Solved successfully ☑

Step-by-step explanation:

➡(2x+3)²=25

Using the identity (a+b) ²=a²+2ab+b²

➡(2x)²+2×2x×3+3²=25

➡4x²+12x+9=25

Subtracting 25 on both sides

➡4x²+12x+9-25=25-25

➡4x²+12x-16=0

➡4x²+16x-4x-16=0

➡4x(x+4)-4(x+4)=0

➡(x+4)(4x-4)=0

So

➡x+4=0 or 4x-4=0

➡x= -4 or x= 4/4

➡x=(-4) or x=1

Proof⤵

➡(2x+3)²=25

Putting the value of x= 1 and (-1)

➡(2×1+3)²=2²+2×2×3+3²=4+12+9=25= RHS

➡(2×(-4) +3) ²=(-8+3) ²=(-5) ²=25=RHS

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Hope this is helpful to you!

Answer 2

Answer:

Hey! there , here is your right answers

good night btw I don't know sanskrit dear mate. sorry

I have no sufficient space to give u full answers so I hope u know now, what u have to do?