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Answered by
7
Heya !!
2X² + 3√5 X + 5
=> 2X² + √5X + 2√5X + 5
=> X ( 2X + √5 ) + √5 ( 2X + √5 )
=> ( 2X + √5 ) ( X + √5 ) = 0
=> ( 2X + √5 ) = 0 Or ( X + √5 ) = 0
=> X = -√5/2 or X = -√5
2X² + 3√5 X + 5
=> 2X² + √5X + 2√5X + 5
=> X ( 2X + √5 ) + √5 ( 2X + √5 )
=> ( 2X + √5 ) ( X + √5 ) = 0
=> ( 2X + √5 ) = 0 Or ( X + √5 ) = 0
=> X = -√5/2 or X = -√5
Answered by
3
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2 x^2 + 3 √5 x + 5 = 0
2 x ^2 + √ 5 x + 2 √ 5 x + 5 = 0
Taking commons !
x ( 2 x + √ 5 ) + √ 5 ( 2 x + √ 5 ) = 0
( 2 x + √ 5 ) or ( x + √ 5 ) = 0
2 x + √ 5 = 0 , x + √ 5 = 0
2 x = - √ 5 , x = - √ 5
x = - √ 5 / 2 , x = - √ 5
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