Question

$( - 2x + 3y + 2z)^{2}$
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Answer 1

here is your answer hope it helps

Answer 2

Answer:

$(-2x+3y+2z)^{2}=4x^{2}+9y^{2}+4z^{2}-12xy+12yz-8zx$

Step-by-step explanation:

We have-

$(-2x+3y+2z)^{2}$

We know that:-

$(a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$

So,

$(-2x+3y+2z)^{2}$ = $(-2x)^{2}+(3y)^{2}+(2z)^{2}+2(-2x).(3y)+2.(3y).(2z)+2.(2z).(-2x)$

= $4x^{2}+9y^{2}+4z^{2}-12xy+12yz-8zx$

Hence-

$(-2x+3y+2z)^{2}=4x^{2}+9y^{2}+4z^{2}-12xy+12yz-8zx$