Question

$2x + 3y = 32$
$11y - 9x = 3$
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Answer 1

Answer:

$multiply \: equation \: 1 \: by \: 9 \: and \: equation \: 2 \: by \: 2$

$18x + 27y = 288$

$22y - 18x = 6$

$add \: both \: new \: equations$

$18x + 27y + 22y - 18x = 288 + 6$

$27y + 22y = 294$

$49y = 294$

$y = \frac{294}{49}$

$y = 6$

$we \: know \: that \: 2x + 3y = 32$

$substitute \: the \: value \: of \: y \: in \: the \: equation$

$2x + 3 \times 6 = 32$

$2x + 18 = 32$

$2x = 32 - 18$

$2x = 14$

$x = \frac{14}{2}$

$x = 7$

$therefore \: \: \: x = 7\: \: and \: \: y = 6$

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