Math, asked by starunikasruti, 8 months ago

$(2x - y + z) {?}^{2} expand$

Answers

Answered by spichhoredot123

Step-by-step explanation:

$<font color=red>$ (2x- y + z)²

(2x- y + z)² (2x- y + z)²

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Answered by Anonymous

Given -

$(2x - y + z)$

To find -

Expanded form

Solution -

By using identity V we will solve this problem.

${2x}^{2} + {(- y)}^{2} + {z}^{2} + 2(2 \times -y) + 2( - y \times z) + 2(z \times 2x)$

${4x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4zx$

(some important points)

▹ This is a 3-4 steps answer.

▹ In this the value of y was in negative but when we multiplied it twice it became positive.

▹ After ${4xy}$ I have put a negative sign as y is in negative sign and 2 is in positive sign so ( + - = -) therefore the sign will change into negetive too.

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Some more identities -

$({x} + y) {}^{2} = {x}^{2} + 2xy + {y}^{2}$

${(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

$(x + a)(x + b) = {x}^{2} + (a + b)x + (a \times b)$

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Answers

(2x- y + z)²

(2x- y + z)² (2x- y + z)²

$(2x - y + z) {?}^{2} expand$

$<font color=red>$ (2x- y + z)²