Question

$2y + 1 \div 2y = 5$
then find the value of
$4y2 + 1 \div 4y2$
​

Answer 1

Answer:

oof I was going to ask the same question now

Answer 2

Answer:

$\\ \frac{2y + 1}{2y} = 5 \\ 2y + 1 = 10y \\ 8y = 1 \\ y = \frac{1}{8}$

Now,

$\frac{4 {y}^{2} + 1}{4 {y}^{2} } \\ = \frac{ {y}^{2} + \frac{1}{4} }{ {y}^{2} } \\ = \frac{ \frac{1}{64} + \frac{1}{4} }{ \frac{1}{64} } \\ = {1 + 16} \\ = 17$