factorise
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Answer:
2y^2+3√5y+5
BY FACTORISATION METHOD,
2y^2+√5y+2√5y+5
y(2y+√5) + √5(2y +√5)
(y+√5)(2y+√5)=0
y = -√5, -√5/2
HOPE IT HELPS YOU.
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