Question

$2y {}^{2} - 5y + 10 = 0$
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Answer 1

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Answer 2

Answer

$⇒2 {y}^{2} - 5y + 10 = 0$

$\colorbox{h} {copyright with } {ay }^{2} + by + c = 0$

we get

$⇒a= 2, b=-5,c=10$

$⇒△ = {b}^{2} - 4ac$

$⇒( - 5 {)}^{2} - 4 \times 2 \times 10$

$⇒25 - 80$

$⇒△ = - 55$

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