Question

${2y} + {27y} + 13 = 0$
Solve the quadratic equation by factorisation with L. H. S. in two linear factors. ​

Answer 1

Answer:

2y^2-26y-y+13=0

2y (y-13)-1 (y+13)

(2y-1)(y+13)

y=1/2 &-13

Answer 2

I think your question is 2y^2+27y+13=0

Hence your answer is..........

2y^2+27y+13=0

2y^2+26y+y+13=0

2y(y+13) +1(y+13) =0

(2y+1) (y+13) =0

2y+1=0 or y+13=0

y=-1/2 or y=-13