Question

$2y - 3 < y + 2 \leqslant 3y + 5$
​

Answer 1

Step-by-step explanation:

we have,

$2y - 3 < y + 2 \: = > 2y - y < 2 + 3$

$= > y < 5 \: \: ......(i)$

And,

$y + 2 \leqslant 3y + 5$

$2y \geqslant - 3$

$= > y \geqslant \frac{ - 3}{2} \: ....(ii)$