Question

$2y2 + 27y + 13 = 0$
please it's argent!
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Answer 1

$\huge\mathfrak \color{pink}AnSwEr:-$

$2 {y}^{2} + 27y + 13 = 0$

$2 {y}^{2} +2 7y = - 13$

$29 {y}^{3} = - 13$

${y}^{3} = \frac{ - 13}{29}$