Question

$(3 {}^{0 } \div 4 {}^{ - 1} ) \times 2 {}^{2}$
please insert formula ​

Answer 1

Ans:- (3^0 ÷ 4^-1) × 2^2

= (1 ÷ 1/4) × 4

= (1×4) × 4

= 4 × 4

= 16

here is your answer

hope it will help you