Question

$3.011 \times {10}^{23} of \: ammonia \: gas \: molecules \: calculate \: molar \: volume$
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Answer 1

we know that

1 mole gas=22.4 litre volume=6.022*10^23 particles

since no. of particles are 3.011*10^23=(6.022*10^23)/2

therefore no. of moles of ammonia gas=0.5 mol

therefore volume=22.4/2=11.2 Litres

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