Question

$(3 {}^{ - 1} \times 9 { }^{ - 1} ) \div {3}^{ - 2}$
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Answer 1

1/3

Step-by-step explanation:

$(3 {}^{ - 1} \times 9 {}^{ - 1} ) \div 3 {}^{ - 2}$

$(3 \times 9) {}^{ - 1} \div 3 {}^{ - 2}$

$27 {}^{ - 1} \div 3 {}^{ - 2}$

$3 {}^{ - 3} \div 3 {}^{ - 2}$

=$3 {}^{ - 1}$

$= \frac{1}{3}$

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