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0
hello....
here is your answer...
3 - 12 ( a^2 + b^2 - 2ab)
3 - 12a^2 - 12b^2 + 24ab
hope it helps
#jerri
here is your answer...
3 - 12 ( a^2 + b^2 - 2ab)
3 - 12a^2 - 12b^2 + 24ab
hope it helps
#jerri
mayur41:
further u can solve by removing 3 common
Answered by
1
Given Equation is 3 - 12(a - b)^2.
We know that (a-b)^2 = a^2 + b^2 - 2ab.
Then 3 - 12(a - b)^2
= 3 - 12(a^2 + b^2 - 2ab)
= 3 - (12a^2 + 12b^2 - 24ab)
= 3 - 12a^2 - 12b^2 + 24ab
= -3(1 + 2a - 2b)(2a - 2b - 1).
Hope this helps!
We know that (a-b)^2 = a^2 + b^2 - 2ab.
Then 3 - 12(a - b)^2
= 3 - 12(a^2 + b^2 - 2ab)
= 3 - (12a^2 + 12b^2 - 24ab)
= 3 - 12a^2 - 12b^2 + 24ab
= -3(1 + 2a - 2b)(2a - 2b - 1).
Hope this helps!
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