Question

$(3 {}^{2} ) {}^{3} +( \frac{2}{3} ) { {}^{0} } + 3 {}^{5}$
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Answer 1

Answer:

$\left(3^2\right)^3+\left(\dfrac{2}{3}\right)^0+3^5=973$

Step-by-step explanation:

$\left(3^2\right)^3+\left(\dfrac{2}{3}\right)^0+3^5$

$\gray{\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0}$

$\gray{\left(\dfrac{2}{3}\right)^0=1}$

$=\left(3^2\right)^3+1+3^5$

$\black{\left(3^2\right)^3}$

$\gray{\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}}$

$=3^{2\cdot \:3}$

$\gray{\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6}$

$=3^6$

$=3^6+1+3^5$

$\gray{3^6=729}$

$=729+1+3^5$

$\gray{3^5=243}$

$=729+1+243$

$\gray{\mathrm{Add\:the\:numbers:}\:729+1+243=973}$

$=973$