Math, asked by rupanvirkaur, 11 months ago


(3 {}^{2} ) {}^{3}  +( \frac{2}{3} ) { {}^{0} }  + 3 {}^{5}

Answers

Answered by AbhijithPrakash
3

Answer:

\left(3^2\right)^3+\left(\dfrac{2}{3}\right)^0+3^5=973

Step-by-step explanation:

\left(3^2\right)^3+\left(\dfrac{2}{3}\right)^0+3^5

\gray{\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0}

\gray{\left(\dfrac{2}{3}\right)^0=1}

=\left(3^2\right)^3+1+3^5

\black{\left(3^2\right)^3}

\gray{\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}}

=3^{2\cdot \:3}

\gray{\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6}

=3^6

=3^6+1+3^5

\gray{3^6=729}

=729+1+3^5

\gray{3^5=243}

=729+1+243

\gray{\mathrm{Add\:the\:numbers:}\:729+1+243=973}

=973

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