Question

$(3 + 2 \sqrt{2} ) + (3 - 2 \sqrt{2 } ) = 6 \: \: \: how$

Answer 1

(3 + 2√2)  + (3 - 2√2)

= 3 + 2√2 + 3 - 2√2

= 3 + 3 + 2√2 - 2√2

= 6

Answer 2

$Bonjour! \\ \\ = > (3 + 2 \sqrt{2 }) + (3 - 2 \sqrt{2} ) \\ \\ = > 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2} \\ \\ = > 6 \: \: \: \: \: \: \: \: \: (answer) \\ \\ Hope \: this \: helps...:)$