Question

$3 + 2 \sqrt{2} + \frac{1}{3 + 2 \sqrt{2} }$
Pls solve this !!
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Answer 1

Solution :-

$3 + 2 \sqrt{2} + \frac{1}{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ 3 + 2 \sqrt{2} + \frac{3 - 2 \sqrt{2} }{9 - 8} \\ \\ 3 + 2 \sqrt{2} + 3 - 2 \sqrt{2} = 3 + 3 = 6 \: \: \: ans$

Thanks! ❤️

Answer 2

Answer:

Hey mate the answer is 6.

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