Question

${3}^{2n - 1} \times {9}^{1 - n}$
indices question no 2 sub question 8
plz give answer as fast as possible​

Answer 1

3^2n-1 x 3^2(1-n)
3^2n-1 x 3^2-2n

Now bases are same
So powers can be added

3^2n-1+2-2n
3^2-1
3^1
3

Answer 2

Step-by-step explanation:

$3 {}^{2n - 1} \times 9 {}^{1 - n}$

$2 {7}^{2n - 1(1 - n)}$

$27 ^{2n ^{2} + n }$

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