Question

$3 {}^{5x} \div {3}^{x} = \sqrt[5]{343}$
then fine value of x​

Answer 1

Answer:

value of "x" is $\frac{1}{4}$

Step-by-step explanation:

I'm sorry, but I think you copied a task with mistake.

If original is

$3^{5x}$ ÷ $3^{x}$ = $\sqrt[5]{243}$ , then

$3^{5x-x}$ = $\sqrt[5]{3^5}$

$3^{4x}$ = $3^{1}$ ===> 4x = 1 ===> x = $\frac{1}{4}$