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Answered by
10
Hi,
Here's the solution :-
3(a+b)^2 - 2a -2b -8
= 3(a+b)^2 -2 (a+b) - 8
[Taking a+b as common ]
= (a+b) {3(a+b)-2} -8
= (a+b)(3a+3b) - 8
I hope that this is correct.
Here's the solution :-
3(a+b)^2 - 2a -2b -8
= 3(a+b)^2 -2 (a+b) - 8
[Taking a+b as common ]
= (a+b) {3(a+b)-2} -8
= (a+b)(3a+3b) - 8
I hope that this is correct.
Answered by
0
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