Question

$3 \div 6 + 2 \div 3$
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Answer 1

$3 \div 6 + 2 \div 3 \\1 \div 2 + 2 \div 3 \\ \\ \frac{1}{2} + \frac{2}{3 } \\ \\ \frac{(3 \times 1) + (2 \times 2)}{3} \\ \\ \frac{3 + 4}{3} \\ \\ \frac{7}{3}$

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Answer 2

Answer:

\begin{gathered}3 \div 6 + 2 \div 3 \\1 \div 2 + 2 \div 3 \\ \\ \frac{1}{2} + \frac{2}{3 } \\ \\ \frac{(3 \times 1) + (2 \times 2)}{3} \\ \\ \frac{3 + 4}{3} \\ \\ \frac{7}{3} \end{gathered}

3÷6+2÷3

1÷2+2÷3

2

1

+

3

2

3

(3×1)+(2×2)

3

3+4

3

7

Hope it's helpful to you