Math, asked by sanjaykumarkumar, 10 months ago


3 \sqrt{1 + 3 + 5 + 7 + ........53}
Please answer these ​

Answers

Answered by Anonymous
1

Answer:

1+3+5+7......+53

since given series in AP

d=2

a=1

n=53

sn=53/2{2+(53-1)2}

Sn=53*106/2

Sn=53^2

now putting the value in the question we get

sqrt53^2

53

Step-by-step explanation:

formula sum of n term of an AP

Sn=n/2{2a+(n-1)d}

a =first term

d=common difference

n=last term

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