Math, asked by debbarmap957, 2 months ago


(3 +  \sqrt{2) } (2 +  \sqrt{2) {}^{2} }

Answers

Answered by saireddy461
0

Answer

Step By Step explanation:

(3+\sqrt{2})(2+\sqrt{2})^2=(3+\sqrt{2})((2)^2+(\sqrt{2})^2+2(2)(\sqrt{2}))\\(3+\sqrt{2})(2+\sqrt{2})^2= (3+\sqrt{2})(4 + 2 + 4\sqrt{2})\\(3+\sqrt{2})(2+\sqrt{2})^2= (3+\sqrt{2})(6 + 4\sqrt{2})\\(3+\sqrt{2})(2+\sqrt{2})^2= 18 + 12\sqrt{2} + 6\sqrt{2} + 4(2)\\(3+\sqrt{2})(2+\sqrt{2})^2= 18 + 18\sqrt{2} + 8\\(3+\sqrt{2})(2+\sqrt{2})^2= 36 + 18\sqrt{2}

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