Question

$3 \sqrt{2} - 2 \sqrt{3 \\ } \\ \\ 3 \sqrt{2} + 2 \sqrt{3}$
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Answer 1

(3$\sqrt{2}$ - 2$\sqrt{3}$) (3$\sqrt{2}$ + 2$\sqrt{3}$)

ID=> (a-b) (a+b) = $a^{2} - b^{2}$

$(3\sqrt{2} )^{2}$ - $(2\sqrt{3} )^{2}$

= (9x2) - (4x3)

= 18 - 12

= 6

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