Question

$3 \sqrt{3} + 2 \sqrt{27 } + 7 \div \sqrt{3}$

Answer 1

this is the answer for this question

Answer 2

hiii!!!

here's Ur answer...

$given \: \frac{3 \sqrt{3} + 2 \sqrt{27} + 7}{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} + 2 \sqrt{27} + 7}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{ \sqrt{3}(3 \sqrt{3} + 2 \sqrt{27} + 7)}{ \sqrt{3} \times \sqrt{3} } \\ \\ = \frac{3 \sqrt{9} + 2 \sqrt{81} + 7 \sqrt{3} }{3} \\ \\ = \frac{(3 \times 3) + (2 \times 9) + 7 \sqrt{3} }{3} \\ \\ = \frac{9 + 18 + 7 \sqrt{3} }{3} \\ \\ = \frac{27 + 7 \sqrt{3} }{3}$

hope this helps..!!