Math, asked by nutandth, 11 months ago


3 \sqrt[3]{250 + } 7 \sqrt[3]{16} - 4 \sqrt[3]{54} \: what \: is \: the \: answer
whatistheanswer​

Answers

Answered by ihrishi
1

Answer:

3  \sqrt[3]{250}  + 7 \sqrt[3]{16}  - 4 \sqrt[3]{54}  \\  = 3  \sqrt[3]{125 \times 2}  + 7 \sqrt[3]{8 \times 2}  - 4 \sqrt[3]{27 \times 2}\\  = 3  \sqrt[3]{ {5}^{3}  \times 2}  + 7 \sqrt[3]{ {2}^{3}  \times 2}  - 4 \sqrt[3]{ {3}^{3}  \times 2} \\ = 3  \times 5 \sqrt[3]{  2}  + 7 \times 2 \sqrt[3]{  2}  - 4  \times 3\sqrt[3]{  2} \\  \:  = 15 \sqrt[3]{  2}  + 14 \sqrt[3]{  2}  - 12\sqrt[3]{  2} \\  = 29 \sqrt[3]{  2}   -  12\sqrt[3]{  2} \\   = 29 \sqrt[3]{  2}   -  12\sqrt[3]{  2} \\   = 17\sqrt[3]{  2}

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