Math, asked by goperaj664, 10 months ago

$3 + \sqrt{5} \div 3 - 2 \sqrt{5}$
a-b√5

Answers

Answered by mohitgurjar59

Answer:

$\huge\mathcal{\purple{answer = \frac{7+ \sqrt[3]{5}}{2}}}$

Step-by-step explanation:

$= \frac{3 + \sqrt{5} }{3 - \sqrt{5} }$

$=\frac{3 + \sqrt{5} }{3 - \sqrt{5} } = \frac{3 + \sqrt{5} }{3 + \sqrt{5} }$

$by \: using \: identity$

${a}^{2} - {b}^{2} = (a - b)(a + b)$

$= \frac{(3 + \sqrt{5)}{(3 + \sqrt{5)} } }{ {3}^{2} - { \sqrt{5} }^{2} }$

$by \: using \: identity$

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2(a)(b)$

$=\frac{ {3}^{2} + { \sqrt{5} }^{2} + 2(3)( \sqrt{5)} }{9 - 5}$

$=\frac{9 + 5 + \sqrt[6]{5} }{4}$

$= \frac{14 + \sqrt[6]{5} }{4}$

By taking 2 common,

$= \frac{7 + \sqrt[3]{5} }{2}$

$<marquee> { hope it help you}$

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