Question

$3 \sqrt{8} + 3 \sqrt{27} + 3 \sqrt{64} =$
solve it with explaination.
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Answer 1

Answer:

$3 \sqrt{8} + 3 \sqrt{27} + 3 \sqrt{64}$

$3 \sqrt{2 \times 4} + 3 \sqrt{3 \times 9} + 3 \sqrt{8 \times 8}$

$3 \times 2 \sqrt{2} + 3 \times 3\sqrt{3} + 3 \times 8$

$6 \sqrt{2} + 9\sqrt{3} + 24$

$3(2 \sqrt{2 } + 3 \sqrt{3} + 8)$

$\sqrt{2} = 1.414 \\ \sqrt{3} = 1.732$

$3(2.828 + 5.196 + 8)$

$48.072$

I have no idea if this is correct.

Please correct me if I'm wrong.

PS. Is that jungkook

I'm new at kpop