Question

$3 \times {10}^{11}$

electrons are flowing through the filament of bulb for two minutes. find the current flowing through the the circuit. Charge on one electron is
$1.6 \times {10}^{19} c$
​

Answer 1

ANSWER:

• The current flowing through the the circuit = 4 × 10⁻¹⁰ A.

GIVEN:

• 3 × 10¹¹ electrons are flowing through the filament of bulb for two minutes.

• Charge on one electron is 1.6 × 10⁻¹⁹ C.

TO FIND:

• The current flowing through the the circuit.

EXPLANATION:

$\bigstar \ \boxed{ \bold{ \large{ \orange{I = \dfrac{Q}{t}}}}}$

$\bigstar \ \boxed{ \bold{ \large{ \purple{Q = ne}}}}$

$\sf \dashrightarrow I = \dfrac{ne}{t}$

$\sf n = 3 \times {10}^{11}$

$\sf e = 1.6 \times {10}^{ - 19} \ C$

$\sf t= 2 \times 60 = 120 \ s$

$\sf \dashrightarrow I = \dfrac{3 \times {10}^{11} \times 1.6 \times {10}^{ - 19}}{120}$

$\sf \dashrightarrow I = \dfrac{3 \times 0.4 \times {10}^{ - 8}}{30}$

$\sf \dashrightarrow I = \dfrac{ 0.4 \times {10}^{ - 8}}{10}$

$\sf \dashrightarrow I = \dfrac{ 4 \times {10}^{ - 9}}{10}$

$\sf \dashrightarrow I = 4 \times {10}^{ - 10} \ A$

Hence the current flowing through the the circuit = 4 × 10⁻¹⁰ A.