Question

$(3 \times 3 {}^{5x}) \div 9 {}^{2x} = \frac{1}{27}$
​

Answer 1

Step-by-step explanation:

$( {3}^{1} \times {3}^{5x} ) \div {9}^{2x} = \frac{1}{27} \\ = \frac{ {3}^{5x + 1} }{ {3}^{4x} } = \frac{1}{ {3}^{3} } \\ = {3}^{5x + 1 - 4x} = {3}^{ - 3} \\ = {3}^{x + 1} = {3}^{ - 3} \\ on \: comparing \: powers \: we \: get \\ x + 1 = - 3 \\ = x = - 4$

Answer 2

the answer is x = -2 I have attached the steps