Question

$3 {x }^{2} + 11x + 10 = 0$
by completing square

Answer 1

$\bf HELLO \: \: DEAR \\ \\ \\ \\ \bf 3x^{2} + 11x + 10 = 0$


"multiply by 3"


$\bf \: 9x^{2} + 33x + 30 = 0 \\ \\ \bf (3x)^{2} + 2(3x)(11/2) + (11/2)^{2} - (11/2)^{2} + 30 = 0 \\ \\ \bf \: (3x + 11/2)^{2} - 121/4 + 30 = 0 \\ \\ \bf \: (3x + 11/2)^{2} = (121 - 120)/4 \\ \\ \bf \: (3x + 1/2)^{2} = 1/4 \\ \\ \bf \: (3x + 11/2)^{2} = (1/2)^{2} \\ \\ \bf (3x + 1/2) = + - (1/2) \\ \\ \\ \bf taking (-) sig. \\ \\ \bf 3x + 11/2 = -1/2 \\ \\ \bf 3x = (-1 - 11)/2 \\ \\ \bf 3x = (-12)/2 \\ \\ \bf x = -6/3 \\ \\ \bf x = -2 \\ \\ \bf \: taking (+)sig. \\ \\ \bf \: (3x + 11/2) = 1/2 \\ \\ \bf \: 3x = (1 - 11)/2 \\ \\ \bf \: 3x = (-10)/2 \\ \\ \bf \: x = -5/3$



$\underline{\bf I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, \: \: THANKS}$