Question

$3 {x}^{2} - 2 \sqrt{6}x + 2 = 0 \: \: solve \: by \: factorisation$
​

Answer 1

Answer:

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$$3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0$$\sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) = 0$$( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) = 0$$x = \sqrt{ \frac{2}{3} }$

Answer 2

$\boxed{\huge{\red{Answer}}}$

_________________________

→ 3x² - √6x - √6x + 2 = 0

→ 3x² - √2×3 x - √2×3 x + 2 = 0

→ 3x² - (√2)(√3)x - (√2)(√3)x + 2 = 0

→ √3x ( √3x - √2 ) -√2 ( √3x - √2 ) = 0

→ (√3x - √2 ) ( √3x - √2 ) = 0

→ x = √2/3 and x = √2/3

_________________________