Math, asked by a8009471, 1 year ago

[tex] 3} x^{2} =2x+8

please help to solve
chapter expansion [/tex]

Answers

Answered by Panzer786
5
Heya !!




3x² = 2x + 8



3x² - 2x - 8 = 0




3x² - 6x + 4x - 8 = 0



3x ( x - 2 ) + 4 ( x - 2 ) = 0



( x - 2 ) ( 3x + 4 ) = 0



( x - 2 ) = 0 or ( 3x + 4 ) = 0



x = 2 or x = -4/3

a8009471: thank you so much
Answered by SillySam
0
3x^2=2x+8 .
3x^2-2x-8=0
3x^2-(6-4)x-8=0
3x^2-6x+4x-8=0
3x (x-2)+4 (x-2)=0
(3x+4)(X-2)=0

x-2=0
X=2

3x+4=0
3x=-4
x=-4/3

HOPE THE ANSWER HELPS YOU. PLS PLS MARK THE ANSWER AS BRAINLIEST
Similar questions