[tex] 3} x^{2} =2x+8
please help to solve
chapter expansion [/tex]
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Answered by
5
Heya !!
3x² = 2x + 8
3x² - 2x - 8 = 0
3x² - 6x + 4x - 8 = 0
3x ( x - 2 ) + 4 ( x - 2 ) = 0
( x - 2 ) ( 3x + 4 ) = 0
( x - 2 ) = 0 or ( 3x + 4 ) = 0
x = 2 or x = -4/3
3x² = 2x + 8
3x² - 2x - 8 = 0
3x² - 6x + 4x - 8 = 0
3x ( x - 2 ) + 4 ( x - 2 ) = 0
( x - 2 ) ( 3x + 4 ) = 0
( x - 2 ) = 0 or ( 3x + 4 ) = 0
x = 2 or x = -4/3
a8009471:
thank you so much
Answered by
0
3x^2=2x+8 .
3x^2-2x-8=0
3x^2-(6-4)x-8=0
3x^2-6x+4x-8=0
3x (x-2)+4 (x-2)=0
(3x+4)(X-2)=0
x-2=0
X=2
3x+4=0
3x=-4
x=-4/3
HOPE THE ANSWER HELPS YOU. PLS PLS MARK THE ANSWER AS BRAINLIEST
3x^2-2x-8=0
3x^2-(6-4)x-8=0
3x^2-6x+4x-8=0
3x (x-2)+4 (x-2)=0
(3x+4)(X-2)=0
x-2=0
X=2
3x+4=0
3x=-4
x=-4/3
HOPE THE ANSWER HELPS YOU. PLS PLS MARK THE ANSWER AS BRAINLIEST
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