if this has real and equal roots.... find the roots
plzzzzz help
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3
Answer:
x = 2/√3
Step-by-step explanation:
3x² - 4√3x + 4 = 0
We use the formula :-
x = [-b ± √(b²-4ac)] ÷ 2a
If we get b² - 4ac > 0, we will have real roots
If we get b² - 4ac = 0, we have repeated roots
If we get b² - 4ac < 0, we have imaginary roots
So here, a = 3, b = -4√3 and c = 4
b² - 4ac = (-4√3)² - 4 x 3 x 4
= 48 - 48
= 0
So we have repeated roots -
x = [ -(-4√3) ±√0] / 2(3)
= 4√3 ÷ 6
= 2√3 ÷ 3
x = 2/√3
Hope this helps! :)
AccioNerd:
Thanks for marking as brainliest!
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